Answer:
δ₂ = 15.07 mm
Step-by-step explanation:
Given :
When the leading edge,
is 2.2 m, then boundary layer thickness,δ₁ = 10 mm = 0.01 m
= 5 m
Now we know that for a laminar flow, the boundary layer thickness is
δ =
-------(1)
and Reyonlds number, Re is
------(2)
where ρ is density
v is velocity
x is distance from the leading edge
μ is dynamic viscosity
from (1) and (2), we get
δ∝

Therefore,


δ₂ = 15.07 mm
Therefore, boundary layer thickness is 15.07 mm when the leading edge is 5 m.