Question

A 450 MWt combined cycle plant has a Brayton cycle efficiency of 24% and a Rankine cycle efficiency of 29% with no heat augmentation. Determine the net electric output from the plant.

Answer 1

Output of plant=207.18 MW

Step-by-step explanation:

Given input energy Q=450 MW

Brayton cycle efficiency
`\eta_1=24`%

Rankine cycle efficiency
`\eta_2=29`%

Combined efficiency for two cycle given as follow

`\eta _b=\eta _1+\eta _2-\eta _1\eta _2`

`\eta _b=0.24+0.29-0.24* 0.29`

`\eta_b=0.4604`

We know that efficiency
`\eta =(out\ put)/(in\ put)`

out put of plant=
`450* 0.4604`

So output of plant=207.18 MW