Question

A 2.5-m3 tank contains air at 240 °C and 175 kPa. The air is then heated under constant pressure conditions to a final temperature of 400 °C. Calculate the final volume and the mass of the air inside the tank.

Answer 1

m= 2.97 Kg

V₂= 3.28 m³

Step-by-step explanation:

V₁=2.5 m³ P₁= 175 kPa T₁=240 ⁰C = 240+273= 513 K

R=0.287 (characteristic gas constant)

according to ideal gas equation

P₁V₁=mRT₁

`m=(P_1V_1)/(RT_1)`

`m=(175* 2.5 )/(0.287* 513)`

m= 2.97 Kg

T₂=400 °C= 400+273 = 673 K P₁=P₂= 175 kPa

P₂V₂=mRT₂

`V_2=(mRT_2)/(P_2)`

`V_2=(2.97 * 0.287 * 673)/(175)`

V₂= 3.28 m³