Question

5 kg of air (R 287 J/kgK) fills a weighted piston-cylinder device at 50 kPa and 0°C. The device is heated until the temperature is 100°C. Determine the initial volume, the final volume, and the work done during this process.

Answer 1

143.5 KJ

Step-by-step explanation:

We have given mass=5 kg

vlaue of R Which is a constant =287 J/kgk

P=50 KPa

T₁=0°C=273K

T₂=100°C=100+273=373K

we know the standard equation of ideal gas=PV=mRT

Here we have to calculate volume using above equation

v₁=\frac{287\times 5\times 273}{50\times 1000}

v₁=7.833
`m^(3)`

for constant pressure

`(V1)/(T1)`=
`(V2)/(T2)`

Using this formula

v₂=
`(373)/(273)`×7.8351

=10.705
`m^(3)`

work done = Pdv

=50×
`10^(3)`×(10.7051-7.8351)

=143.5 KJ