Question

A coil of conducting wire carries a current i. In a time interval of Δt = 0.520 s, the current goes from i1 = 3.20 A to i2 = 1.90 A. The average emf induced in the coil is e m f = 14.0 mV. Assuming the current does not change direction, calculate the coil's inductance (in mH).

Answer 1

5.6 mH

Step-by-step explanation:

i1 = 3.20 A, i2 = 1.90 A, e = 14 mV = 0.014 V,

Let L be the coil's inductance.

`e = -L* (\Delta i)/(\Delta t)`

`0.014 = -L* (1.90 - 3.20)/(0.52)`

L = 0.0056 H

L = 5.6 mH