Question

A baseball approaches home plate at a speed of 44.0 m/s, moving horizontally just before being hit by a bat. The batter hits a pop-up such that after hitting the bat, the baseball is moving at 53.0 m/s straight up. The ball has a mass of 145 g and is in contact with the bat for 2.20 ms. What is the average vector force the ball exerts on the bat during their interaction?

Answer 1

Step-by-step explanation:

It is given that,

Speed of the baseball, u = 44 m/s

Speed of the baseball, v = 53 m/s

Mass of the ball, m = 145 g = 0.145 kg

Time of contact between the ball and the bat, t = 2.2 ms = 0.0022 s

`F=ma`

`F=(mv)/(t)`

`F_1=(0.145\ kg* 44\ m/s)/(0.0022\ s)`

F₁ = 2900 N...........(1)

`F=ma`

`F=(mv)/(t)`

`F_2=(0.145\ kg* 53\ m/s)/(0.0022\ s)`

F₂ = 3493.18 N.........(2)

In average vector form force is given by :

`F=F_1+F_2`

`F=(2900i+(-3493.18)\ N`

`F=(2900i-3493.18j)\ N`

Hence, this is the required solution.