Question

2. The Food and Drug Administration (FDA) mandates that all vinegar sold in the United States must have a minimum concentration of 4% acetic acid by mass. Calculate the minimum molarity of acetic acid in vinegar according to this standard. Assume the density of vinegar is the same as for water.

Answer 1

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

Step-by-step explanation:

4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.

Given that density of the vinegar is same is that of water = 1 g/mL

Mass of the vinegar solution = 100 g

Volume of the vinegar solution = V

`Density=(Mass)/(Volume)`

`1 g/mL=(100 g)/(V)`

V = 100 mL = 0.1 L

Moles of acetic acid =
`(4 g)/(60.052 g/mol)=0.0666 mol`

`Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}`

`M=(0.0666 mol)/(0.1 L)=0.6660 mol/L`

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.