Answer with Step-by-step explanation:
A six-sided number cube is rolled twice.
The sample space is:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Total outcomes=36
The outcomes with an even number on first roll and number greater than 4 on second roll are in bold letters
Total number of favorable outcomes=3
P(an even number on first roll and number greater than 4 on second roll)
= number of favorable outcomes/total number of outcomes
= 3/36
= 1/12
Hence, probability of an even number on first roll and number greater than 4 on second roll is:
1/12