Question

An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of the electric force on this electron due to this field

Answer 1

`2.24 * 10^(-14)` Newtons

Step-by-step explanation:

Magnitude of charge on the electron = q =
`1.6 * 10^(-19)` Coulombs

The negative sign in the question statement indicates that the charge is negative.

Magnitude of Electric Field experienced by the electron = E =
`1.4 * 10^(5)` Newtons/Coulomb

Magnitude of Force on the electron = F = ?

The relation between the charge, electric field and the force on the charge because of electric field is given by:

`E=(F)/(q)`

From here we can write:

F = qE

Using the values, we get:

`F = 1.6 * 10^(-19) * 1.4 * 10^(5)\\\\ F = 2.24 * 10^(-14)`

Thus, the magnitude of the electric force experience by the electron would be
`2.24 * 10^(-14)` Newtons