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Find the angle between the given vectors to the nearest tenth of a degree. u = <6, 4>, v = <7, 5>

User Tmighty
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1 Answer

4 votes

Answer: 1.8°

Explanation:

To calculate the angle between the vectors u and v we use the formula of the dot product.

The dot product between two vecotores is:


u\ *\ v = |u||v|*cosx

Where x is the angle between the vectors

As we know the components of both vectors, we calculate the dot product by multiplying the components of both vectors


u=6i + 4j\\v=7i +5j

Then:


u\ *\ v = 6*7 + 4*5


u\ *\ v = 42 + 20


u\ *\ v =62

Now we calculate the magnitudes of both vectors


|u|=√(6^2 + 4^2)\\\\|u|=2√(13)


|v|=√(7^2 +5^2)\\\\|v|=√(74)

Then:


62 = 2√(13)*√(74)*cosx

Now we solve the equation for x


62 = [tex]cosx=(62)/(2√(13)*√(74))\\\\x=arcos((62)/(2√(13)*√(74)))\\\\x=1.8\°

User Michal J Figurski
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5.9k points