Answer: 1.8°
Explanation:
To calculate the angle between the vectors u and v we use the formula of the dot product.
The dot product between two vecotores is:

Where x is the angle between the vectors
As we know the components of both vectors, we calculate the dot product by multiplying the components of both vectors

Then:



Now we calculate the magnitudes of both vectors


Then:

Now we solve the equation for x
![62 = [tex]cosx=(62)/(2√(13)*√(74))\\\\x=arcos((62)/(2√(13)*√(74)))\\\\x=1.8\°](https://img.qammunity.org/2020/formulas/mathematics/high-school/uux68l6lgbw7fsyiekrghsbc7bby0a2fw7.png)