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What stereochemistry do you expect for the alkene obtained by E2 elimination of (1R,2R)-1,2-dibromo-1,2-diphenylethane? Draw a Newman projection of the reacting conformation.

User Paul Morie
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Answer:

Z-isomer of the alkene is formed.

Step-by-step explanation:

E2 elimination occurs in the presence of a strong base. It is a bimolecular elimination reaction in which the rate depends both on the concentration of the alkyl halide and the base.

The elimination reaction occurs in a single step. For E2 to happen, Hydrogen at the α-C and the halogen must be anti periplanar to each other or the angle between them is equals to 180°.

The reaction of (1R,2R) -1,2-dibromo-1,2-diphenylethane with a strong base gives (Z)-1-bromo-1,2-diphenylethene. The mechanism is shown in image one. Z-isomer of the alkene is formed.

The Newman projection of the reacting conformation is shown in image 2.

What stereochemistry do you expect for the alkene obtained by E2 elimination of (1R-example-1
What stereochemistry do you expect for the alkene obtained by E2 elimination of (1R-example-2
User Louis T
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