114k views
5 votes
A point charge q is located at the center of a cube whose sides are of length a. If there are no other charges in this system, what is the electric flux through one face of the cube?

User BBrill
by
6.2k points

1 Answer

4 votes

Answer:


\phi_E=(q)/(6\epsilon_o)

Step-by-step explanation:

Given: A charge q is enclosed within the cube

The length of the one side of cube = a

Now, according to the Gauss Law the net flux (
\phi_E) through the closed surface containing the charge q is:


\phi_E=\oint \vec{E}.\vec{ds}=(q_o)/(\epsilon_o)

where,
\epsilon_o} is the permittivity

This electric flux is for the 6 faces of the cube

thus, for the one face of the cube the electric flux will be
\phi_E=(q)/(6\epsilon_o)

User Jurgenreza
by
6.5k points