Question

the solubility of N2 in water is 0.00090 m when the partial pressure above the liquid is 1.6 atm. At what pressure is the solubility equal to 0.00030m

Answer 1

The pressure is 0.53 atm

Step-by-step explanation:

Given that,

Solubility C₁ = 0.00090 m

Solubility C₂ = 0.00030 m

Pressure P₁ = 1.6 atm

We need to calculate the pressure

Solubility directly proportional to partial pressure,

`C_(1)\propto P_(1)`.....(I)

`C_(2)\propto P_(2)`....(II)

From equation (I) and (II)

`(C_(1))/(P_(1))=(C_(2))/(P_(2))`

Where, C = solubility

P = pressure

Put the value into the formula

`(0.00090)/(1.6)=(0.00030)/(P_(2))`

`P_(2)=(1.6*0.00030)/(0.00090)`

`P_(2)=0.53\ atm`

Hence, The pressure is 0.53 atm