Question

What is the average power dissipated by a resistor of resistance R = 25 Ω in an LRC circuit for which the power factor is equal to 0.25 and the maximum voltage of the AC source is 8 V?

Answer 1

0.08 w

Step-by-step explanation:

AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.

the expression for the average power is given as

P=
`V_r`
`I_r` cosΦ

We have given maximum voltage =8 volt

`V_r`=
`(8)/(1.414)`

power factor =.25

resistance =25Ω

power factor =
`(R)/(Z)`

power factor=
`(25)/(Z)`

From here Z=100

P=
`(8)/(1.414)` ×
`(v_r)/(Z)` ×cosΦ

=5.6577×0.05677×0.25

=0.08w