Question

When 0.511 g of sodium metal is added to an excess of hydrochloric acid, 5310 J of heat are produced. What is the enthalpy of the reaction as written?

Answer 1

The the enthalpy of the reaction is 241.36 KJ.

Step-by-step explanation:

Given that,

Weight of sodium = 0.511 g

We need to calculate the number of moles

Using formula of moles

`moles=(given\ mass)/(molar\ mass)`

`moles=(0.511)/(23)`

`moles= 0.022`

We need to calculate the energy in 1 mole

In 0.022 moles of sodium metal = 5310 J

In 1 moles of sodium metal =
`(5310)/(0.022)`

The Energy in 1 moles of sodium is 241363.63 J.

Hence, The the enthalpy of the reaction is 241.36 KJ.