Question

A rectangular bar has a depth of d = 7 cm and a height of h = 3 cm . The bar is subjected to an axial load P = 400 N . What is the magnitude of the shear force on a plane at an angle θ = 50 ∘

Answer 1

SHEAR FORCE = 257.11 N

Step-by-step explanation:

given data:

depth d = 7 cm

height h = 3 cm

P = 400 N

Area of cross section normal to P = 30*70 = 2100 mm2

Area of cross section (inclined portion) = A'

`sin\theta =(A)/(A^('))`

`A^(')= (A)/(sin\theta)`

`A^(')= (2100)/(sin50)`

A' =2741.35 mm2

Taking summation of vertical force

`V-Pcos\theta = 0`

v = 400*cos50° = 257.11 N

Average shear force =
`(v)/(A')`

Average shear force =
`(257.11)/(2741.35) = 0.093 MPa`