Question

What is the resistivity of a wire of 1.3 mm diameter, 2.3 m length, and 61 ms resistance. Number Units The number of significant digits is set to 2; the tolerance is +/-2%

Answer 1

`\rho = 3.68 *10^(-8) Ω. m`

Step-by-step explanation:

The resistance is given as

`R = (\rho L)/(A)`

Where A IS Cross sectional area of wire
`= \pi r^(2)`

therefore resistivity \rho can be wrtten as

`\rho = (\pi Rd^(2))/(4L)`

Putting all value to get resistivity value
`\rho =(\pi* 61*10^(-3)* (1.33*10^(-3))^(2))/(4*2.3)`

`\rho = 3.68 *10^(-8) Ω. m`