Question

The container is fitted with a piston so that the volume can change. When the gas is heated at constant pressure, it expands to a volume of 25 L. What is the temperature of the gas in kelvins?

Answer 1

`T_(2)` =
`(25T_(1))/(V_(1))`

where

`V_(1)` is initial volume in liters

`T_(1)` is initial temperature in kelvins

Step-by-step explanation:

Let the initial volume be
`V_(1)` and the initial temperature be
`P_(1)`

Now by ideal gas law

`(P_(1)V_(1))/(T_(1))=nR..............(i)`

Similarly let

`V_(2)` be final volume

`T_(2)` be the final volume

thus by ideal gas law we again have

`(P_(2)V_(2))/(T_(2))=nR..............(ii)`

Equating i and ii we get

`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`

For system at constant pressure the above expression reduces to

`(V_(1))/(T_(1))=(V_(2))/(T_(2))`

Solving for
`T_(2)` we get

`T_(2)` =
`(25T_(1))/(V_(1))`

where

`V_(1)` is initial volume in liters

`T_(1)` is initial temperature in kelvins