Question

g Determine the magnetic field midway between two long straight wires 2.0 cm apart in terms of the current I in one when the other carries 25 A. Assume these currents are in the same direction.

Answer 1

`B_(net)` =
`(2* 10^(-5)T/A).(I-25A)`

Step-by-step explanation:

Given :

the distance between the two wires is = 2 cm

= 0.02 m

Current in one of the wire, I = 25 A

Now we know that, when the direction of the current is same that is in one direction , the magnetic field at the mid point in between the two wires will oppose each other.

Therefore we know that

`B_(net)` =
`(\mu _(o)* I_(1))/(2\pi r_(1))-(\mu _(o)* I_(2))/(2\pi r_(2))`

=
`((4\pi * 10^(-7)T.m/A))/(2\pi (1* 10^(-2)m))* (I-25A)`

=
`(2* 10^(-5)T/A).(I-25A)`