Answer with explanation:
To Prove: Sum of Interior angles of triangle is 180°.
Proof:
In ΔABC
Draw line l, parallel to BC.
∠1=∠2------(1)
∠3=∠4------(2)
As lines are parallel , So Alternate Interior angles are equal.
→→Angles, ∠1,∠3, and ∠5 lie on a line.That, is they form a linear pair.Sum of Angles in linear pair is 180°.
∠1+∠3+∠5=180°
→∠2+∠4+∠5=180°-------[Using 1 and 2]
⇒∠A + ∠B+ ∠C=180°