225k views
3 votes
A 120-V rms voltage at 60.0 Hz is applied across an inductor, a capacitor, and a resistor in series. If the rms value of the current in this circuit is 0.600 A, what is the impedance of this circuit?

User Jenneh
by
5.8k points

2 Answers

5 votes

Final answer:

The impedance of the circuit is 200 ohms.

Step-by-step explanation:

The impedance of an RLC series circuit can be calculated using the formula Z = √(R^2 + (Xl - Xc)^2), where Z is the impedance, R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.

In this case, the resistance is 120V rms and the current is 0.600A rms. We can rearrange the formula to solve for Z: Z = Vrms / Irms.

Substituting the values, we have Z = 120V rms / 0.600 A rms = 200 ohms.

User Jens Peter
by
5.5k points
2 votes

Answer:

The impedance of this circuit is 200 ohm.

Step-by-step explanation:

Given that,

rms voltage = 120 v

Frequency = 60.0 Hz

rms current = 0.600 A

We need to calculate the impedance

Using formula of impedance


Z=(V_(rms))/(I_(rms))

Where,
V_(rms) = rms voltage


I_(rms) = rms current

Z= impedance

Put the value into the formula


Z=(120)/(0.600)


Z=200\ Omega

Hence, The impedance of this circuit is 200 ohm.

User Kendrick Lamar
by
6.3k points