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Which of the following has the greatest number of particles? Which of the following has the greatest number of particles? 22.990 g of Na 1 mole of Na 9.012 g of Be 1 mole of Be All are the same.

User Gulzar
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1 Answer

6 votes

Answer: All the given options have the same number of particles.

Step-by-step explanation:

For the given options:

  • Option 1: 22.990 g of Na

According to mole concept:

1 mole of an atom contains
6.022* 10^(23) number of atoms.

If, 22.99 g of sodium metal contains
6.022* 10^(23) number of atoms.

So, 22.990 g of sodium metal will contain
(6.022* 10^(23))/(22.99)* 22.990=6.022* 10^(23) number of atoms.

Number of particles =
6.022* 10^(23)

  • Option 2: 1 mole of Na

According to mole concept:

1 mole of an atom contains
6.022* 10^(23) number of atoms.

So, 1 mole of sodium element will also contain
6.022* 10^(23) number of atoms.

Number of particles =
6.022* 10^(23)

  • Option 3: 9.012 g of Be

According to mole concept:

1 mole of an atom contains
6.022* 10^(23) number of atoms.

If, 9.01 g of beryllium metal contains
6.022* 10^(23) number of atoms.

So, 9.012 g of beryllium metal will contain
(6.022* 10^(23))/(9.01)* 9.012=6.022* 10^(23) number of atoms.

Number of particles =
6.022* 10^(23)

  • Option 4: 1 mole of Be

According to mole concept:

1 mole of an atom contains
6.022* 10^(23) number of atoms.

So, 1 mole of beryllium element will also contain
6.022* 10^(23) number of atoms.

Number of particles =
6.022* 10^(23)

Hence, all the options have same number of particles which is
6.022* 10^(23)

User Carcamano
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