Question

A uniform electric field of magnitude 365 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 3.00 cm. (a) What is the work done by the field on the electron?

Answer 1

`W= 1.752*10^\left ( -18\right )`
`Joules`

Step-by-step explanation:

given E= 365 N/C in positive x-direction

electron initially at rest q= 1.6
`*10^(-19)`C

force experienced by the electron F= Eq

⇒F= 365
`*1.6*10^(-19)`

=584
`*10^(-19)`

Distance traveled by electron S = 3 cm

now work done W= F
`*`S=584
`*`
`10^(-19)`
`*3`
`*10^(-2)`

W= 1752
`*10^\left (-21 \right )` Joules

Work done= 1.752
`*10^\left (-18 \right )` Joules