Answer: First option is correct.
Explanation:
Since we have given that
probability that an individual is left handed = 0.11
Probability that an individual is not left handed = 1-0.11 = 0.89
so, we need to find the probability of finding five left handers.
We will use "Binomial distribution":
P(X=5)=
![^(29)C_5(0.11)^5(0.89)^(24)=0.11](https://img.qammunity.org/2020/formulas/mathematics/college/kon0651w6xqf94zf3b6fcwotlxl1f1s0yl.png)
Hence, the probability of finding five left handers is 0.11.
Therefore, First option is correct.