Question

A sample of an ideal gas has a volume of 2.28 L at 2.80×102 K and 1.12 atm. Calculate the pressure when the volume is 1.27 L and the temperature is 304 K.

Answer 1

Answer: The pressure when the volume and temperature has changed is 2.18 atm

Step-by-step explanation:

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1,V_1\text{ and }T_1` are the initial pressure, volume and temperature of the gas

`P_2,V_2\text{ and }T_2` are the final pressure, volume and temperature of the gas

We are given:

`P_1=1.12atm\\V_1=2.28L\\T_1=2.80* 10^2K=280K\\P_2=?atm\\V_2=1.27L\\T_2=304K`

Putting values in above equation, we get:

`(1.12atm* 2.28L)/(280K)=(P_2* 1.27L)/(304K)\\\\P_2=2.18atm`

Hence, the pressure when the volume and temperature has changed is 2.18 atm