Answer:
Explanation:
P\left ( defective item\right )=0.035
Using binomial distribution
Where p= probability of success
q=probability of failure
Here p=0.035
q=1-0.035=0.965

(i)for exactly 3 defective items i.e. r=3
P
=


P=

P=0.1317
(ii)No defective item i.e. r=0
P
=



P=

P=0.2085
(iii)At least 1 defective item
P=1-P(zero defective item)
P=1-

P=1-


P=0.6671