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A constant magnetic field of 0.50 T is applied to a rectangular loop of area 3.0 × 10-3 m2. If the area of this loop changes from its original value to a new value of 1.6 × 10-3 m2 in 1.6 s, what is the emf induced in the loop?

User Louis XIV
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1 Answer

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Answer:

e= 0.440 mV(millivolt)

Step-by-step explanation:

Given Magnetic field B= 0.50T


A_(1)=3*10^(-3)


A_(2)=1.6*10^(-3)\\

Δt= 1.6sec


induced emf e=\frac{\mathrm{d} \phi }{\mathrm{d} t}


e=B\frac{\mathrm{d} A}{\mathrm{d} t}


e=0.50*(3*10^(-3)-1.6*10^(-3))/(1.6)


e=0.440*10^(-3) volt

e= 0.440 mV(millivolt)

User Britton
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