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If the diffusion coefficient doubles, and the average diffusion distance across a membrane remains the same, what can be said about the time it takes to cross the membrane g

User Notz
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1 Answer

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Answer:

time taken will be halved

Step-by-step explanation:

we have


t=(x^(2))/(2D) ..................(1)

where

t = time elapsed since diffusion began


x^(2) = mean distance traveled by the diffusion solute

D = Diffusion coefficient

now, according to the conditions given in the question

when, diffusion coefficient (D) doubles i.e D' = 2D

Average diffusion distance remains same i.e
x' = x

substituting the values in the equation we get


t=(x'^(2))/(2D')

or


t=(x^(2))/(2(2D))

or


t=(x^(2))/(4D) ...............(2)

hence, on comparing equation (1) and (2) we can say that the time taken will be halved when the diffusion coefficient doubles and the mean distance traveled remains the same

User Tengomucho
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