Answer:
847.45 N
Step-by-step explanation:
F₁=force of exerted by smaller piston
F₂=force of exerted by larger piston=1.44×10⁴ N
A₁=Area of smaller piston= 2.62 cm =0.0265 m
A₂=Area of larger piston= 10.8 cm =0.108 m
Pressure exerted by both the pistons will be equal
![P_1=P_2\\\Rightarrow (F_1)/(A_1)=(F_2)/(A_2)\\\Rightarrow F_1=(F_2)/(A_2) A_1\\\Rightarrow F_1=(14400)/(\pi* 0.108^2)\pi* 0.0262^2\\\Rightarrow F_1=847.45\ N](https://img.qammunity.org/2020/formulas/physics/college/mu9v3x8izegu4w86jhhsw083xbrl2b0ceu.png)
Hence, force exerted to lift a 14400 N car is 847.45 N