Answer:
C. 26.4 kJ/mol
Step-by-step explanation:
The Chen's rule for the calculation of heat of vaporization is shown below:
![\Delta H_v=RT_b\left [ (3.974\left ( (T_b)/(T_c) \right )-3.958+1.555lnP_c)/(1.07-\left ( (T_b)/(T_c) \right )) \right ]](https://img.qammunity.org/2020/formulas/chemistry/college/jv54tna65tste3z41aydnsm0k4culn762w.png)
Where,
is the Heat of vaoprization (J/mol)
is the normal boiling point of the gas (K)
is the Critical temperature of the gas (K)
is the Critical pressure of the gas (bar)
R is the gas constant (8.314 J/Kmol)
For diethyl ether:



Applying the above equation to find heat of vaporization as:
![\Delta H_v=8.314*307.4 \left [ (3.974\left ( (307.4)/(466.7) \right )-3.958+1.555ln36.4)/(1.07-\left ( (307.4)/(466.7) \right )) \right ]](https://img.qammunity.org/2020/formulas/chemistry/college/cdx8nxmzank9f272gbjg2pxvspmb2almdv.png)

The conversion of J into kJ is shown below:
1 J = 10⁻³ kJ
Thus,

Option C is correct