Question

Help please! I need answers quickly :((

Answer 1

y = -
`(1)/(2)` x + 2

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m =
`(0-2)/(4-0)` =
`(-2)/(4)` = -
`(1)/(2)`

The line crosses the y- axis at (0, 2) ⇒ c = 2

y = -
`(1)/(2)` x + 2 ← equation of line

Answer 2

x + 2y = 4

Explanation:

The y intercept (where it crosses the y axis) is (0,2)

Another point on the line is (4,0)

We can find the slope from these two points

m = (y2-y1)/(x2-x1)

= (0-2)/(4-0)

=-2/4 = -1/2

We have the slope and the y intercept

y = mx+b where m is the slope and b is the y intercept

y = -1/2x +2

We want the equation of the line in standard form

Ax +By =C

Add -1/2x to each side

1/2x +y = -1/2x +1/2x +2

1/2x +y = 2

Multiply by 2 because we do not want fractions

2(1/2x +y) = 2* 2

x + 2y = 4