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Prove: For all sets AB,and CIA-B) U (A n B) = A

User Jim Balter
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Answer:

Explanation:

(A-B)U (A∩B) [ We know that difference of A and B is A∩B')

A∩B')U(A∩B)

A∩(B'UB) (Using Distributive law)

A∩(U) [ Union of a set and its complement is always a universal set]

A Hence proved

User Nirmal Goswami
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