Question

A thin conducing plate 2.3 m on a side is given a total charge of −20.0 µC. (Assume the upward direction is positive.) (a) What is the electric field (in N/C) 1.0 cm above the plate? (Indicate the direction with the sign of your answer.)

Answer 1

The electric field is
`-2.14*10^(5)\ N/C`

Step-by-step explanation:

Given that,

Distance = 2.3 m

Charge
`q= -20.0\ \muC`

We need to calculate the electric field

Using formula of electric field

`E=(\sigma)/(2\epsilon_(0))`

Where,
`\sigma=(Q)/(A)`

Q = charge

A = area

Put the value into the formula

`E=(Q)/(2A\epsilon_(0))`

`E=(-20.0*10^(-6))/(2*2.3*2.3*8.85*10^(-12))`

`E=-213599.91\ N/C`

`E=-2.14*10^(5)\ N/C`

Negative sign shows the direction of the electric field.

The direction of electric field is toward the plates.

Hence, The electric field is
`-2.14*10^(5)\ N/C`