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Match the functions to their ranges when the domain is {1, 2}. f(x) = 3x + 5 f(x) = x2 – 2x – 5 f(x) = (x + 5)x2 f(x) = 4 – x {-6, ­-5} arrowRight {8, 11} arrowRight {3, 2} arrowRight {6, 28} arrowRight

2 Answers

3 votes

Answer:Given below

Explanation:


\left ( a\right )


F\left ( x\right )=3x+5

for x=1
F\left (1\right )=8


x=2 F\left ( 2\right )

and domain is {1,2}

range{8,11}


\left ( b\right )


F\left ( x\right )=x^2-2x-5

for x=1
F\left (1\right )=-6

x=2
F\left ( 2\right )=-5

range{-6,-5}


\left ( c\right )


F\left ( x\right )=x^2\left ( x+5\right )

for x=1
F\left (1\right )=6

for x=2
F\left (2\right )=28

Range{6,28}


\left ( d\right )


F\left ( x\right )=4-x

for x=1
F\left (1\right )=3

for x=2
F\left (2\right )=2

range {2,3}

User Hendrik
by
5.2k points
2 votes

Answer:

  • 3x +5 ⇒ (8, 11)
  • x²-2x-5 ⇒ (-6, -5)
  • (x+5)x² ⇒ (6, 28)
  • 4-x ⇒ (3, 2)

Explanation:

Evaluate each function for x=1. This result will let you select the correct answer choice for each function.

To check your result, you can evaluate each function for x=2. You should get the same answer choice in each case.

I find it convenient to let a calculator do the tedious work.

Match the functions to their ranges when the domain is {1, 2}. f(x) = 3x + 5 f(x) = x-example-1
User Saliom
by
5.2k points