Answer:
Part a)

Since focal length is negative so its a diverging lens
Part b)

Since the magnification is position for diverging lens so it is ERECT
Step-by-step explanation:
Part a)
As we know by lens formula



Part b)
Since focal length is negative so its a diverging lens
Part c)
As we know that



Part d)
Since the magnification is position for diverging lens so it is ERECT
Part e)