Question

In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 5.4 m/s in 2.6 s. assuming that the player accelerates uniformly. Determine the distance he runs.

Answer 1

Distance, x = 6.99 meters

Step-by-step explanation:

It is given that,

Initially, the object is at rest, u = 0

Final speed of the basketball player, v = 5.4 m/s

Time taken, t = 2.6 s

Let x is the distance covered by the player. We need to find x. The acceleration of the player is :

`a=(v-u)/(t)`

`a=(5.4\ m/s)/(2.6\ s)=2.07\ m/s^2`

Now, calculating the distance covered by the player using second equation of motion as :

`x=ut+(1)/(2)at^2`

`x=0+(1)/(2)* 2.07\ m/s^2* (2.6\ s)^2`

x = 6.99 meters

So, the distance covered by the basketball player is 6.99 meters.