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In a binary system, what is the maximum number of phases that can co-exist under the equilibrium conditions? One a b Two Three C d Four

User Setlio
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1 Answer

3 votes

Answer:

D) Four

Step-by-step explanation:

Using phase rule,

F = C - P + 2

where,

C is the number of components in the system. For example, for binary systems, C=2

P indicates the number of phase of the component. It is defined as homogeneous chemical composition of the substance. Thus, two immiscible liquids with definite boundaries form 2 phases.

F is the number of variables. For example , variables like temperature, pressure, mole fraction, etc.

Thus, using this

C =2

For P to be maximum, F has to be 0. This is the condition when all the variable of the binary system is known.

So,

F = C - P + 2

0 = 2 - P + 2

P = 4

User Toskan
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