Answer:
The graph in the attached figure
Explanation:
we have
![y-1=(2)/(3)(x-3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iuf0crgwi1eh78p9zsa07dp4rc41ct4iti.png)
This is the equation of the line into point slope form
The slope is m=2/3
The point is (3.1)
To easily identify the graph look for the intercepts of the line
The y-intercept is the value of y when the value of x is equal to zero
For x=0
![y-1=(2)/(3)(0-3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/juef1fha80942swewzkuvdbfwgkadkm4o0.png)
![y=-2+1=-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qcbstzx6lcmuoci7ka93dltd2of07mlc5b.png)
The y-intercept is the point (0,-1)
The x-intercept is the value of x when the value of y is equal to zero
For y=0
![0-1=(2)/(3)(x-3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ve0zit2s3bhs7owzcygkp551pm9t1hmhv1.png)
![-3=2x-6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nabw554y6frsffg566w435sh4vhfkd5guz.png)
![2x=3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h8jckuymuw6z6wd2rp9hwbytbemrjftstc.png)
![x=1.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3uqbygpipxdumgtlclptnc72dl1bze0qq6.png)
The x-intercept is the point (1.5,0)
Plot the intercepts and join the points to identify the graph
using a graphing tool
The graph in the attached figure