Answer:
30°
Explanation:
Since ΔACD is isosceles with congruent sides AC = CD , then
∠ADC = ∠CAD
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ACB is an exterior angle of ΔACD, hence
∠ACD + ∠CAD = 60° , thus
2 ∠ADC = 60 ( divide both sides by 2 )
∠ADC = 30°