Question

Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(1).

Answer 1

`\large\boxed{(h\circ g)(1)=8}`

Explanation:

`(f\circ g)(x)=f\bigg(g(x)\bigg)\\===================\\\\(h\circ g)(1)=h\bigg(g(1)\bigg)\\\\g(1)-\text{put}\ x=1\ \text{to the equation of the function}\ g(x)=2x:\\\\g(1)=2(1)=2\\\\h\bigg(g(1)\bigg)=h(2)-\text{put}\ x=2\ \text{to the equation of the function}\ h(x)=x^2+4:\\\\h(2)=2^2+4=4+4=8`