Question

If a 167.6 pound person consumes 3.3 liters of oxygen per minute at maximal exercise intensity, calculate their relative VO2max. Report your answer to the nearest 10th of a ml/kg/min.

Answer 1

`4.340844077* 10^(-5)`

Explanation:

`VO_(2max)` is known as the maximum rate of oxygen consumption per minute

here we have to calculate
`VO_(2max)` with respect to body weight which is given as 167.6 pound

relative
`VO_(2max)` = maximum milliliters of oxygen consumed in one minute/ body weight in milligram

given consumption of oxygen =3.3 liters/minute

=3300 mil liters

176.6 pound =76022081 milligram

so relative
`VO_(2max)`=
`(3300)/(76022081)` ml/mg/min

=0.000043408441 ml/mg/min