Question

If a 2500 kg truck is placed on a garage lift platform with an area of 3 m ^ 2, what area would the input piston have to have to lift the truck with 25 lb of force

Answer 1

A_1 = 0.0135 m2

Step-by-step explanation:

GIVEN DATA:

mass of SECOND truck m2 =2500 kg

mass of FIRST truck m1 = 25 lb = 11.33kg

Area A2 = 3 m2

according to the pascal's law, pressure at one point is equal to pressure exerted on the other side, therefore we have

`P_(1 )= P_(2)`

we know that

`pressure = (force)/(area)`

`(f_(1))/(A_(1)) =(f_(2))/(A_(2))`

`A_(2) =(f_(2))/(F_(1))* A_(1)`

`A_(2) = (m_(2))/(m_(1))*A_(1)`

`3 = (2500)/(11.33)*A_(1)`

A_1 = 0.0135 m2