Answer:
![P(B|C)=(9)/(24)=0.38](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3bpsvubuj7hiz2bl279npnfu0hp8un82t3.png)
Explanation:
The formula for conditional probability :-
![P(M|N)=(P(M\cap N))/(P(N))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iszq0ayvv3w1dzzrc8gnbz88gu50zojxs0.png)
From the given table it can be seen that ,
Total = 70
![n(C)=24](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y6isf9myacg8l06fug398wacfbl6npwzbh.png)
Then , the probability of having B:-
![\text{P(C)}=\frac{\text{n(C)}}{\text{Total}}\\\\=(24)/(70)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k4tgx25hd94mko3yo9nmmx5jz3nyrehna7.png)
Also,
![n(B\cap C)=9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mwzcovqttf2w9jcwnlzuzmwx9tuhpzsf15.png)
Then , the probability of having the intersection of B and C :-
![P(B\cap C)=\frac{n(B\cap C)}{\text{Total}}\\\\=(9)/(70)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2wnyun91gmc1jjv8vh67tz701s8behpxev.png)
Then , by the formula of conditional probability , we have :-
![P(B|C)=(P(B\cap C))/(P(C))\\\\=((9)/(70))/((24)/(70))\\\\=(9)/(24)=(3)/(8)=0.375\approx0.38](https://img.qammunity.org/2020/formulas/mathematics/middle-school/62v5zdayanzpo4r06rycgvrg2uqe7a0gpf.png)