A wire carries 3.7 A of current. A second wire is placed parallel to the first 8.0 cm away. What is the current flowing through the second wire if the magnitude of the wires is …

Question

asked Feb 19, 2020 235k views

1 Answer

Nohat · Answer 1 · 2020-02-25T05:25:12+0000

Answer:

The current in second wire is 5.0 A.

(B) is correct option.

Step-by-step explanation:

Given that,

Current in first wire = 3.7 A

Distance = 8.0 cm

We need to calculate the magnetic field due to the current carrying wire

Using formula of magnetic field

$B=(\mu_(0)I)/(2\pi r)$

Where, I = current

r = distance

Put the value into the formula

For first wire

$B = (\mu_(0)*3.7)/(2\pi *3.4*10^(-2))$ ...(I)

For second wire,

The distance is 8-3.7 = 4.3 cm

$B' = (\mu_(0)* I')/(2\pi *(8-3.4)*10^(-2))$ ...(II)

The magnetic field in both the wires,

From equation (I) and (II)

$(\mu_(0)*3.7)/(2\pi *3.4*10^(-2))= (\mu_(0)* I')/(2\pi *(8-3.4)*10^(-2))$

I'=(3.7*4.3*10^(-2))/(3.4*10^(-2))

$I'=4.68\ A\ approx = 5.0\ A$

Hence, The current in second wire is 5.0 A.