Question

The plates of a spherical capacitor have radii 6.25 cm and 15.0 crn. The space between the two spheres is filled with a material with dielectric constant of 4.8 Calculate the capacitance. Put your answer in the form of .abc x 100). F?

Answer 1

Capacitance is 0.572×10⁻¹⁰ Farad

Step-by-step explanation:

Radius = R₁ = 6.25 cm = 6.25×10⁻² m

Radius = R₂ = 15 cm = 15×10⁻² m

Dielectric constant = k = 4.8

Electric constant = ε₀ = 8.854×10⁻¹² F/m

ε/ε₀=k

ε=kε₀

`Capacitance\ (C)=(4\pi k\epsilon_0 R_1* R_2)/(R_2-R_1)\\\Rightarrow C=(4\pi 4.8* 8.854* 10^(-12)* 15* 10^(-2)* 6.25* 10^(-2))/(15* 10^(-2)-6.25* 10^(-2))\\\Rightarrow C=0.572* 10^(-10)\ Farad`

∴ Capacitance is 0.572×10⁻¹⁰ Farad