Question

Find the x-intercepts (if any) for the graph of the quadratic function below. 6 y+4=(x-2)^2 a) (0, 0) and (-4, 0) b) (0, 0) and (4, 0) c) (0, 0) d) (-4, 0) and (4, 0) e) none

Answer 1

The function has two x-intercepts at (0,0) and (4,0).

Explanation:

Consider the provided function.

`y+4=(x-2)^2`

The x-intercepts are the point, where y is 0.

To find x-intercepts, substitute y = 0 in the provided equation and solve for x.

`0+4=(x-2)^2`

`4=(x-2)^2`

`\pm√(4)=x-2`

`\pm2=x-2`

`2=x-2` or
`-2=x-2`

`2+2=x` or
`-2+2=x`

`4=x` or
`0=x`

Therefore, the function has two x-intercepts at (0,0) and (4,0).