Question

A particle of mas 0.1 kg moves along the trajectory x(t)-3t t where x is in meters and t is in seconds. What is the kinetic energy of the particle at time t? Select one: a. 0.3 (t 1)3 o b. 0.25 (t2 -1) c. 0.25 (t + 1)2 d. 0.45 (t2+1)2 o e. 3.0 (1-)

Answer 1

Kinetic energy = 0.45 joules

Step-by-step explanation:

We have velocity of the particle is

`v=(dx(t))/(dt)\\\\v=(d(3t))/(dt)\\v=3m/s`

Now kinetic energy(K.E) is given by

`K.E=(1)/(2)mv^(2)`

applying values we get

Kinetic energy =
`(1)/(2)0.1* 3^(2)\\\\\therefore K.E=0.45Joules`