Question

Find the equation of the line that passes through the points (-3,0) and (4,2). Using point slope formula

Answer 1

`\large\boxed{y-0=(2)/(7)(x+3)}\\\downarrow\\\boxed{y=(2)/(7)x+(6)/(7)}`

Explanation:

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

m - slopei

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

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We have the points (-3, 0) and (4, 2).

Substitute:

`m=(2-0)/(4-(-3))=(2)/(7)`

Put the value of the slope and the coordinates of the point (-3, 0) to the equation:

`y-0=(2)/(7)(x-(-3))`

`y-0=(2)/(7)(x+3)`

Converto to the slope-intercept form (y = mx + b):

`y=(2)/(7)x+(6)/(7)`