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Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?

A) All integers where n ≥ 1
B) All integers where > 1
C) All integers where n ≥ 4
D) All real numbers

User Rokridi
by
7.5k points

2 Answers

7 votes

Answer:

The answer is A. All integers where n > 1

Explanation:

The domian for n is restricted and cannot be less than 1 and the domain is the x value while 4 would be a y value.

User Marlo Guthrie
by
8.6k points
4 votes

Answer:

The correct option is A.

Explanation:

According to statement a1 = 4 and r = 3. This shows that r is greater than 1.

If r is greater than 1 than it includes integers greater than 1 or equal to 1. It does not include all the real numbers because real numbers include negative numbers also.

If starting value is 4,if we put n=0, then we get 4, but if we put a negative value than we would get a number which is not a part of our sequence. Thus the correct option is All integers where n ≥ 1....

User Kangax
by
8.7k points

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