Question

Find the mean, median, mode, range of 2.3, 4.5, 6, 7.4, 6.8

Answer 1

look below

Explanation:

ordered numbers-2.3,4.5,6,6.5,7.4

1.mean:average

sum of numbers divided by 5

=5.4

2. median is middle number

=6

3.mode most frequent number

each number is different and therefore there is no mode

4. range:

max-min

7.4-2.3

=5.1

Answer 2

Explanation:

Measures of Central Tendency

• Mean: 5.4
• Median: 6
• Mode: 2.3,4.5,6,6.8,7.4

Mean:

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values. The formula for the mean of a population is

`\mu = \frac{{\sum}x}{N}`

The formula for the mean of a sample is

`\bar{x} = \frac{{\sum}x}{n}`

Both of these formulas use the same mathematical process: find the sum of the data values and divide by the total. For the data values entered above, the solution is:

`(27)/(5) = 5.4`

Median:

The median of a data set is found by putting the data set in ascending numerical order and identifying the middle number. If there are an odd number of data values in the data set, the median is a single number. If there are an even number of data values in the data set, the median is the average of the two middle numbers. Sorting the data set for the values entered above we have:

`2.3, 4.5, 6, 6.8, 7.4`

Since there is an odd number of data values in this data set, there is only one middle number. With 5 data values, the middle number is the data value at position 3. Therefore, the median is 6.

Mode:

The mode is the number that appears most frequently. A data set may have multiple modes. If it has two modes, the data set is called bimodal. If all the data values have the same frequency, all the data values are modes. Here, the mode(s) is/are

`2.3,4.5,6,6.8,7.4`

Range:

The range is found by subtracting the smallest data value from the largest data value. Here, the smallest data value is 2.3 and the largest is 7.4. Therefore, the range is:

`7.4 - 2.3 = 5.1`

Thanks,

Eddie